Avarage program in c

#include<stdio.h>
#include<conio.h>
main()
{
int m,p,c,total,avarage;
clrscr();
printf("\n enter the three subject marks");
scanf("%d%d%d",&m,&p,&c)
total=m+p+c;
avarage=total/3;
printf("\n total is %d",total);
printf("\n avarage is %d",avarage);
getch();
}


OUTPUT:

enter the three subject marks 20 20 20
total is 60
avarage is 20